Answer:
0.2298
Step-by-step explanation:
Number of pieces of candy A in the bag = 20
Number of pieces of candy B in bag =10
Total number of pieces =10+20=30
Probability of picking candy A first [tex]=\frac{20}{30}[/tex]
Now total number of pieces in the bag =30-1=29 as one piece of candy A is picked out
Now the probability of picking of candy B[tex]=\frac{10}{29}[/tex]
So the required probability [tex]=\frac{20}{30}\times \frac{10}{29}=0.2298[/tex]