Question

If the average (arithmetic mean) of the assessed values of x houses is $212,000 and the average of the assessed values of y other houses is $194,000, what is the average of the assessed values of the x y houses?

Answer 1

Answer: Our required average would be

$Average=\dfrac{212000x+194000y}{x+y}$

Step-by-step explanation:

Since we have given that

Average of assessed values of x houses = $212,000

Average of assessed values of y houses = $194,000

As we know the formula,

$Average=\dfrac{\text{Assessed value of x houses}}{x}\\\\212,000=\dfrac{\text{Assessed value of x houses}}{x}\\\\212,000x=\text{Assessed value of x houses}$

Similarly,

$Average=\dfrac{\text{Assessed value of y houses}}{x}\\\\194,000=\dfrac{\text{Assessed value of y houses}}{x}\\\\194,000x=\text{Assessed value of y houses}$

So, Average of the assessed values of the xy houses would be

$Average=\dfrac{\text{Assessed value of x houses +Assessed value of y houses}}{x+y}\\\\Average=\dfrac{212000x+194000y}{x+y}$

Hence, our required average would be

$Average=\dfrac{212000x+194000y}{x+y}$