Consider a galvanic (voltaic) cell that has the generic metals X and Y as electrodes. If X is more reactive than Y (that is, X more readily reacts to form a cation than Y does), classify the following descriptions by whether they apply to the X or Y electrode.

anode
cathode
electrons in the wire flow toward
electrons in the wire flow away
cations from salt bridge flow toward
anions from salt bridge flow toward
gains mass
loses mass

Respuesta :

Consider a galvanic (voltaic) cell that has the generic metals X and Y as electrodes. If X is more reactive than Y (that is, X more readily reacts to form a cation than Y does), classify the following descriptions by whether they apply to the X or Y electrode.

Further explanation

  • Anode: X
  • Cathode : Y
  • Electrons in the wire flow toward : Y
  • Electrons in the wire flow away : X
  • Cations from salt bridge flow toward : y
  • Anions from salt bridge flow toward : X
  • Gains mass : Y
  • Loses mass: X

Because X is more reactive than Y, So X is oxidized to X²⁺ and Y²⁺ is reduced to Y. Therefore the overall cell reaction is:

X(s) + Y²⁺(aq) → X²⁺(aq) + Y(s)

X electrode: Electrons in the wire flow away from, Anions from the salt bridge flow toward, Anode, Loses mass

Y electrode: Electrons in the wire flow toward, Cations from the salt bridge flow toward, Cathode, Gains mass

Learn more

  1. Learn more about  galvanic (voltaic) cell  https://brainly.com/question/10161182
  2. Learn more about the generic metals https://brainly.com/question/2146012
  3. Learn more about cathode https://brainly.com/question/3218763

Answer details

Grade:  9

Subject:  chemistry

Chapter:  a galvanic (voltaic) cell

Keywords:  galvanic (voltaic) cell, the generic metals, cathode, anode, salt bridge

Electrons flow from anode to cathode in a voltaic cell.

A voltaic cell is one in which electrical energy is produced by a redox reaction. Electrons flow from anode to cathode in a voltaic cell and the cell reaction is spontaneous.

Given a generic voltaic cell in which metal X is more reactive than metal Y, it follows that;

  • X will be the anode and Y will be the cathode
  • Electrons in the wire will flow away from X and flow towards Y
  • Anions in the salt bridge flow towards X while cations in the salt bridge flow towards Y.
  • There will be a gain in mass at Y and a loss in mass at X.

Learn more: https://brainly.com/question/1340582

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