The period of a mass-spring system is:
T = 2π[tex]\sqrt{m/k}[/tex]
T = period, m = mass, k = spring constant
Given values:
T = 8π s
k = 2 N/m
Plug in and solve for m:
8π = 2π[tex]\sqrt{m/2}[/tex]
[tex]\sqrt{m/2}[/tex] = 4
m/2 = 16
m = 32 kg
Choice A
The answer is 32 kg.
The period of a mass-spring system is:
T = 2π
T = period, m = mass, k = spring constant
Given values:
T = 8π s
k = 2 N/m
Plug in and solve for m:
8π = 2π
= 4
m/2 = 16
m = 32 kg.
A mass suspended on a spring will oscillate after being displaced. The duration of oscillation is laid low with the amount of mass and the stiffness of the spring. This experiment allows the period, displacement, velocity, and acceleration to be investigated by data logging the output from a motion sensor.
Inside the spring-mass gadget, oscillations arise due to the fact, that on the static equilibrium displacement, the mass has kinetic electricity that's transformed into capability energy saved in the spring at the extremes of its direction.
Learn more about the Spring Oscillator here: https://brainly.com/question/15701473
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