Answer:
The correct answer is 0.53 meters.
Explanation:
The given density of water is 1025 kg/m^3
Gauge pressure, that is, (P2 - P2) = Po/19
Here Po = 1.013 * 10^5 Pa
= 1.0.13 * 10^5 Pa / 19 = 5331.58 Pa
The change in pressure associated with the depth is given by the formula:
P2 -P1 = ρgh
h = P2 - P1 / ρg
h = 5331.58 Pa / 1025 kg/m^3 * 9.8 m/s^2
h = 0.53 m
Thus, the driver can swim 0.53 meters below water.