Four cash prizes ($5000, $2000, $500 and $250) to be awarded to 4 students selected randomly from 15 students ( 7 from UCF and 8 from UF). In how many ways the prizes can awarded?

Respuesta :

Answer:

32760 ways

Step-by-step explanation:

There are overall 15 students from which we have to select 4 students at random for the 4 Cash prizes.

i)                 First Prize can be distributed in [tex]^{15}\textrm{C}_{1}[/tex] ways .

Also here we know the identity which says that

[tex]^{m}\textrm{C}_{1}=m[/tex]

Hence [tex]^{15}\textrm{C}_{1}=15[/tex]

Now we are left with 14 students for second prize.

ii)                   Second prize can be distributed in [tex]^{14}\textrm{C}_{1}=14[/tex]  ways

Now we are left with 13 students for third prize.

iii)                 Third prize can be distributed in [tex]^{13}\textrm{C}_{1}=13[/tex]  ways.

Now we are left with only one prize and which can be distributed among 12 Students

iv)                 Fourth prize can be distributed in [tex]^{12}\textrm{C}_{1}=12[/tex]  ways.

 

Hence total number of ways of distributing 4 prizes among 15 students is

[tex]15 \times 14\times 13\times 12[/tex]

= 32760

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