Respuesta :

Answer:

A. [tex]\frac{x^{2} +h^{2} +2hx }{x+3+h}[/tex]

Step-by-step explanation:

To find f(x+h) you just need to plug in x+h for every value of x

so the new equation would be

[tex]\frac{(x+h)^{2}}{(x+h)+3}\\ =\frac{x^{2} +h^{2} +2hx }{x+3+h}[/tex]

For this case we have the following function:

[tex]f (x) = \frac {x ^ 2} {x + 3}[/tex]

We must find [tex]f (x + h)[/tex], then substituting we have:

[tex]f (x + h) = \frac {(x + h) ^ 2} {(x + h) +3}[/tex]

By definition we have to:[tex](a + b) ^ 2 = a ^ 2 + 2ab + b ^ 2[/tex]

So:

[tex]f (x + h) = \frac {x ^ 2 + 2xh + h ^ 2} {x + h + 3}[/tex]

Answer:

Option A

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