[tex]A(t)=1500(1+\frac{.035}{4})^{(4)(3)}[/tex]Answer:
Step-by-step explanation:
Use the formula
[tex]A(t)=P(1+\frac{r}{n})^{nt}[/tex]
where A(t) is the amount after the compounding is done, r is the interest rate in decimal form, P is the initial investment amount, n is the number of times it compounds per year, and t is the time in years. For us,
A(t) = ?
r = .035
P = 1500
n = 4
t = 3
Therefore,
[tex]A(t)=1500(1+\frac{.035}{4})^{(4)(3)}[/tex] and
[tex]A(t)=1500(1.00875)^{12}[/tex] and
A(t) = 1500(1.11020345) so
A(t) = $1665.31