Question

Suppose the gravitational acceleration on a certain planet is only 4.0 m/s2. A space explorer standing on this planet throws a ball straight upward with an initial velocity of 24 m/s. Assume that upward direction is positive. What is the velocity of the ball 3 seconds after it is thrown?

Answer 1

Answer:

12 m/s

Explanation:

a = 4 m/s^2

u = 24 m/s

t = 3 second

Let the velocity of the ball after 3 second is v.

Use first equation of motion

v = u + a t

v = 24 - 4 x 3

v = 24 - 12 = 12 m/s