Answer:
Step-by-step explanation:
Put hypotheses as:
[tex]H_0: mu =40 mg\\H_a: mu \neq 40 mg.[/tex]
(Two tailed test at 4%)
Since population std deviation is given we can do Z test.
[tex]Sample size n =30\\Sample mean = 42.3 mg\\Mean diff = 2.3 mg\\Std error of sample = \frac{7.1}{\sqrt{30} } =1.296[/tex]
Test statistic t = mean diff/se = [tex]\frac{2.3}{1.296} =1.775[/tex]
p value=0.075
Since p >0.04 our alpha, we accept null hypothesis.
At alphaequals0.04, we cannot reject the company's claim