Answer:
[tex]4\sqrt{17}[/tex]
Step-by-step explanation:
Let's find the answer by using the arc length formula which is:
[tex]\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^{2} } } \, dx[/tex]
First, let's find dy/dx which is:
y=4x-5
y'=4*(1)-0
y'=4, now let's use the formula:
[tex]\int\limits^3_{-1} {\sqrt{1+4^{2}} } \, dx=\sqrt{17} *(3-(-1))=4\sqrt{17}[/tex]
Now, using the distance formula we have:
[tex]d=\sqrt{(x2-x1)^{2} +(y2-y1)^{2} }[/tex]
[tex]y(-1)=4*(-1)-5=-9 \\y(3)=4*(3)-5=7[/tex]
So we have two points (-1, -9) and (3, 7) so:
[tex]d=\sqrt{(3-(-1))^{2} +(7-(-9))^{2} }=4\sqrt{17}[/tex]
Notice both equations gave the same length [tex]4\sqrt{17}[/tex].