what is the value of x?

To solve this you must use Pythagorean theorem:
[tex]a^{2} +b^{2} =c^{2}[/tex]
a and b are the legs (the sides that form a perpendicular/right angle)
c is the hypotenuse (the side opposite the right angle)
In this case...
a = 48
b = x
c = 50
^^^Plug these numbers into the theorem
[tex]48^{2} +x^{2} =50^{2}[/tex]
simplify
2304 + [tex]x^{2}[/tex] = 2500
Isolate x^2 by subtracting 2304 to both sides
[tex]x^{2}[/tex] = 196
To remove the square from x take the square root of both sides to get you...
14 = x
Hope this helped!
~Just a girl in love with Shawn Mendes