What is the value of x that makes PQ←→||RS←→?

Answer:
x = 55
Step-by-step explanation:
For PQ and RS to be parallel then
∠ACQ = ∠RDB ( Alternate exterior angles ), thus
3x - 65 = 2x - 10 ( subtract 2x from both sides )
x - 65 = - 10 ( add 65 to both sides )
x = 55
The value of x that would make the two lines PQ and RS parallel is 55°.
When two parallel lines are cut by a transverse. the angles formed on the exterior of the parallel lines, on the opposite sides of the transverse are known as the Alternate Exterior Angle.
For the two lines, PQ and RS to be parallel, the measure of the ∠RDB and ∠ACQ should be equal, this is because the two angles are on the opposite side of the transverse AB and are both on the exterior side of the line PQ and RS. Therefore, form a pair of alternated exterior angles.
Thus, we can write the measure of the two angles as,
∠RDB = ∠ACQ
2x - 10 = 3x - 65
2x - 3x = -65 + 10
-x = -55
x = 55°
Hence, the value of x that would make the two lines PQ and RS parallel is 55°.
Learn more about the Alternate Exterior Angles:
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