Question

A 13.1 μF capacitor is connected through a 853 kΩ resistor to a constant potential difference of 64 V. Compute the charge on the capacitor at 14 s after the connections are made. (Give your answer in decimal using micro C (μC) as unit)

Answer 1

Answer:

$q = 598.9 \mu C$

Explanation:

As we know that when an uncharged capacitor is connected through a voltage source then the charge on the plates of capacitor will increase with time.

It is given by the equation

$q = CV(1 - e^{-\frac{t}{RC}})$

here we know that

$C = 13.1 \mu F$

$R = 853 k ohm$

V = 64 volts

now we have

$q = (13.1 \mu F)(64) ( 1 - e^{-\frac{14}{(853\times 10^3)(13.1 \times 10^{-6})}})$

$q = 598.9 \mu C$