Answer:
The magnification is -6.05.
Explanation:
Given that,
Focal length = 34 cm
Distance of the image =2.4 m = 240 cm
We need to calculate the distance of the object
[tex]\dfrac{1}{u}+\dfrac{1}{v}=\dfrac{1}{f}[/tex]
Where, u = distance of the object
v = distance of the image
f = focal length
Put the value into the formula
[tex]\dfrac{1}{u}=\dfrac{1}{34}-\dfrac{1}{240}[/tex]
[tex]\dfrac{1}{u}=\dfrac{103}{4080}[/tex]
[tex]u =\dfrac{4080}{103}[/tex]
The magnification is
[tex]m = \dfrac{-v}{u}[/tex]
[tex]m=\dfrac{-240\times103}{4080}[/tex]
[tex]m = -6.05[/tex]
Hence, The magnification is -6.05.