Question

3x^2y^3/9x^8y^6
fully simplify using only positive exponents

Answer 1

Answer:

$\frac{1}{3x^{6} y^{3} }$

Step-by-step explanation:

The inital equation would look like this: $\frac{3x^{2} y^{3} }{9x^{8}y^{6} }$

Then, we simplify. The 3 and the 9 cancel, leaving a 3 on the denominator. Then, the x's cancel, leaving x^(8-2), which is x^6 on the denominator.

The y's cancel out leaving y^(6-3), which is just y^3 on the denominator.

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