Question

If s(x) = x-7 and f(x) = 4x? – X+3, which expression is equivalent to (tos)(x)?
04(x-7)2 – X-7 + 3
0 4(x-7)2 – (x-7) + 3
(4x2 - x + 3)-7
0 (4x2 – x+3)(x-7)

Answer 1

Answer:

4(x-7)^2-(x-7)+3 (Assuming t is f)

Step-by-step explanation:

Let s(x)=x-7 and t(x)=4x^2-x+3 .

(t o s)(x)=t(s(x))=t(x-7)

Before I continue this means replace the orginal x in t with x-7.

This will then give you

4(x-7)^2-(x-7)+3