Answer:
(- 7, - 1), 6 units
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - h)² = r²
where (h, k) are the coordinates of the centre and r is the radius.
Given
x² + y² + 14x + 2y + 14 = 0
Collect x/y terms together and subtract 14 from both sides
x² + 14x + y² + 2y = - 14
To obtain standard form use the method of completing the square
add ( half the coefficient of the x/y terms )² to both sides
x² + 2(7)x + 49 + y² + 2(1)y + 1 = - 14 + 49 + 1
(x + 7)² + (y + 1)² = 36 ← in standard form
with centre (- 7, - 1) and radius = [tex]\sqrt{36}[/tex] = 6