Question

At the equator, near the surface of the Earth, the magnetic field is approximately 50.0 µT northward, and the electric field is about 100 N/C downward in fair weather. Find the gravitational, electric, and magnetic forces on an electron in this environment, assuming the electron has an instantaneous velocity of 5.90 ✕ 106 m/s directed to the east in this environment.

Answer 1

Answer:

$F_g = 8.9 \times 10^{-30} N$

$F_e = 1.6 \times 10^{-17} N$

$F_m = 4.72 \times 10^{-17} N$

Explanation:

For gravitational force we know that

F = mg

now we have

$m = 9.1 \times 10^{-31} kg$

$F_g = (9.1 \times 10^{-31})(9.8)$

$F_g = 8.9 \times 10^{-30} N$

Now electrostatic force

$F = qE$

here we have

$F = (1.6 \times 10^{-19})(100)$

$F = 1.6 \times 10^{-17} N$

Now magnetic force on it is given by

$F_{m} = qvB$

$F_m = (1.6 \times 10^{-19})(5.90 \times 10^6)(50 \times 10^{-6})$

$F_m = 4.72 \times 10^{-17} N$