What is [(x^2y^3)^1/3]/ [^3 √x^2y] in exponential form?

Answer:
answer for question 1 is A and question 2 is B
Step-by-step explanation:
i literally just took the assignment
[tex](x^{2} y^{3})^{1/3}[/tex]/∛x²y in exponential form [tex]x^{2/3}y^{1}[/tex]÷[tex]x^{2/3 }\;y^{1/3} }[/tex].
The correct option is (A)
power defines a base number raised to the exponent, where base number is the factor which is multiplied by itself and
exponent denotes the number of times the same base number is multiplied.
Given function is:
[tex](x^{2} y^{3})^{1/3}[/tex]/∛x²y
Now, using rules of exponents and power
=[tex]x^{2/3} y^{3/3}[/tex]÷[tex]x^{2/3 }\;y^{1/3} }[/tex] [(a²)³= [tex]a^{6}[/tex]]
=[tex]x^{2/3}y^{1}[/tex]÷[tex]x^{2/3 }\;y^{1/3} }[/tex]
Hence, [tex](x^{2} y^{3})^{1/3}[/tex]/∛x²y= =[tex]x^{2/3}y^{1}[/tex]÷[tex]x^{2/3 }\;y^{1/3} }[/tex]
Learn more about exponents and power here:
https://brainly.com/question/15722035
#SPJ2