Answer:
The ball is at its maximum height.
Explanation:
As we know that when ball is thrown at some angle with the horizontal then the component of its velocity is given as
[tex]v_x = vcos\theta[/tex]
[tex]v_y = vsin\theta[/tex]
now here vertical velocity is the velocity in y direction
so it is given as
[tex]v_y = 3.0 sin30 = 1.5 m/s[/tex]
now as the velocity of ball in vertical direction becomes zero
then in that case
[tex]v_f - v_i = at[/tex]
[tex]0 - 1.5 = (-9.8)t[/tex]
[tex]t = 0.15 s[/tex]
since at this position the vertical component of the velocity is zero
so this is the position of ball when its height is maximum