Question

A photon has a wavelength of 3.8 × 10-7 meters, which is between visible and ultraviolet. Calculate the energy of this photon.

Answer 1

use the equation Energy of photon = h * c / wavelength

where h is Planck constant = 6.62607004 × 10-34 m2 kg / s

c is velocity of light in vacuum = 3.00 × 108 m/s and

wavelength value already you know

Answer 2

Answer:

Energy of the photon is $5.2\times 10^{-19}$ J.

Explanation:

Energy of a photon (E) is given by the following equation-

                                              $E=\frac{hc}{\lambda }$

Where h is the plank constant, c is the velocity of light and $\lambda$ is the wavelength of photon.

Hence, $E=\frac{(6.626\times 10^{-34}J.s)\times (3\times 10^{8}m/s)}{3.8\times 10^{-7}m}$

So, E=$5.2\times 10^{-19}$ J