jennydoesthings6238 jennydoesthings6238
  • 19-06-2019
  • Mathematics
contestada

find the area between y=e^x and y=e^2x over [0,1]

Respuesta :

jcherry99
jcherry99 jcherry99
  • 20-06-2019

Answer:

Step-by-step explanation:

Just so you see what you are trying to do, the graph shows you what you are given.

Graph

Red: y = e^x

blue: y = e^(2x)

green x = 1

equations

integral e^(2*x) = e^(2x)/2

integral e^x = e^x

Solution

e^(2x)/2 between 1 and 0 equals e^(*2*1)/2 - e^0

e^(2x) / 2 = 7.3891 - 1 = 6.3891

e^(x )  between 1 and 0 equals e^(1) - e^0

2.7183 - 1

1.7183

The area between 1 and 0 is 6.3891 - 1.7183 = 4.6708

Ver imagen jcherry99
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