Answer:
Option D
Step-by-step explanation:
we have
system A
-x-2y=7 ----> first equation A
5x-6y=-3 ---> second equation A
Multiply the first equation by 5 both sides
(5)*(-x-2y)=7*5 ----> -5x-10y=35
Adds
5x-6y=-3
-5x-10y=35
-----------------
-6y-10y=-3+35
-16y=32
therefore
To get system B, the second equation in system A was replaced by the sum of that equation and the first equation multiplied by 5. The solution to system B will be the same as the solution to system A