Answer:
Part 5) ∠x=122°
Part 6) Option D. ∠x=114°
Part 7) Option B.300π cm^3
Part 8) The volume of the cone is [tex]V=602.88\ in^{3}[/tex]
Part 9) The value of x is 12 cm
Part 10) BC=21 units
Part 11) Option D.reflection across the y-axis
Part 14) [tex]x=15.6\ cm[/tex]
Part 15) B. 5, 12, 13
Step-by-step explanation:
Part 5) What is the value of x?
we know that
∠x+58°=180°------> by supplementary angles
solve for x
∠x=180°-58°=122°
Part 6) What is the value of x?
we know that
The sum of the interior angles of a triangle must be equal to 180 degrees
The measure of the third interior angle of the triangle is equal to
180°-61°-53°=66°
so
66°+∠x=180° -----> by supplementary angles
solve for x
∠x=180°-66°=114°
Part 7) A cylinder has a radius of 5 cm and a height of 12 cm. What is the volume of the cylinder?
we know that
The volume of the cylinder is equal to
[tex]V=\pi r^{2} h[/tex]
we have
[tex]r=5\ cm[/tex]
[tex]h=12\ cm[/tex]
substitute
[tex]V=\pi (5)^{2} (12)[/tex]
[tex]V=300\pi\ cm^{3}[/tex]
Part 8) A cone has a diameter of 12 in. and a height of 16 in. What is the volume of the cone?
we know that
The volume of the cone is equal to
[tex]V=(1/3)\pi r^{2} h[/tex]
we have
[tex]r=12/2=6\ in[/tex] ------> the radius is half the diameter
[tex]h=16\ in[/tex]
substitute
[tex]V=(1/3)(3.14)(6)^{2} (16)[/tex]
[tex]V=602.88\ in^{3}[/tex]
Part 9) Rectangle ABCD is similar to rectangle FGHI. What is the value of x?
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional
In this problem
AB/FG=BC/GH
substitute the values
8/6=x/9
x=9*8/6
x=12 cm
Part 10) Given quadrilateral ABCD ~ quadrilateral JKLM and AD = 14, JM = 6, and KL = 9, what is BC?
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional
so
AD/JM/BC/KL
substitute the values
14/6/BC/9
BC=14*9/6
BC=21 units
Part 11) What transformation was performed on triangle ABC to create triangle A'B'C' ?
we know that
The rule for a reflection over the y -axis is (x,y)→(−x,y)
so
When reflecting across the y- axis the x-values will be multiplied by negative one, but the y-values will not change
This problem is a reflection across the y-axis
Part 14) What is the value of x? Round to the nearest tenth
we know that
Applying the Pythagoras Theorem
[tex]x^{2}=10^{2}+12^{2}\\ \\x^{2}=244\\ \\x=15.6\ cm[/tex]
Part 15) Which set of side lengths defines a right triangle?
we know that
If the set of side lengths defines a right triangle, then must satisfy the Pythagoras Theorem
Verify each case
case A. 6, 8, 11
[tex]11^{2}=6^{2}+8^{2}\\ \\121=100[/tex]
Is not true
therefore
Is not a right triangle
case B. 5, 12, 13
[tex]13^{2}=5^{2}+12^{2}\\ \\169=169[/tex]
Is true
therefore
Is a right triangle
case C. 7, 9, 13
[tex]13^{2}=7^{2}+9^{2}\\ \\169=130[/tex]
Is not true
therefore
Is not a right triangle
case D. 6, 9, 11
[tex]11^{2}=6^{2}+9^{2}\\ \\121=117[/tex]
Is not true
therefore
Is not a right triangle