Question

Suppose y varies directly as x, and y =16 when x= 8. Find y when x= 16

Answer 1

Answer:

$y=32$

Step-by-step explanation:

$Given\ y\ varies\ directly\ as\ x.\\\\y=kx\ \ \ \ \ (where\ k\ is\ a\ constant)\\\\Given\ y=16\ when\ x=8\\\\Substitute\ these\ two\ values\\\\16=k\times 8\\\\k=\frac{16}{8}\\\\k=2\\\\Hence\ y=2x\\\\Now\ take\ x=16\\\\y=2\times 16\\\\y=32$