Question

Consider the chemical equations shown here.

2Na(s) + Cl2(g) → 2NaCl(s)
4Na(s) + O2(g) → 2Na2O(s)

What is the overall equation for the reaction that produces NaCl and O2 from Na2O and Cl2?

Na2O(s) + Cl2(g) --> NaCl(s) + O2(g)

2Na2O(s) + Cl2(g)--> 2NaCl(s) + O2(g)

2Na2O(s) + 2Cl2(g)--> 4NaCl(s) + O2(g)

Answer 1

Answer:

2Na₂O₍s₎+ 2Cl₂₍g₎⇒4 NaCl₍s₎ +O₂₍g₎

Explanation:

The more reactive chlorine gas displaces the less reactive oxygen gas from the compound sodium oxide. The correct equation is C. because the number of each type atom on each side is equal hence the equation is balanced. There are 4 sodium atoms on the left side as there are on the right, 4 chlorine on both sides and two oxygen on both sides.

Answer 2

Answer : The correct equation will be,

$2Na_2O(s)+2Cl_2(g)\rightarrow 4NaCl(s)+O_2(g)$

Explanation :

The given reactions are:

(1) $2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)$

(2) $4Na(s)+O_2(g)\rightarrow 2Na_2O(s)$

Both the given chemical reactions are balanced chemical reaction. So, in order to get the final equation we first multiply equation 1 by 2 and reverse the equation 2 then add both the equations, we get the overall equation for the reaction the produces $NaCl$ and $O_2$ from $Na_2O$ and $Cl_2$

(1) $4Na(s)+2Cl_2(g)\rightarrow 4NaCl(s)$

(2) $2Na_2O(s)\rightarrow 4Na(s)+O_2(g)$

The final reaction will be,

$2Na_2O(s)+2Cl_2(g)\rightarrow 4NaCl(s)+O_2(g)$