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hesh
I think it is A in this statment

D. The square root of 6

The value of the square root of six is √6 = 2.449489742783178...... and it doesn't terminate or terms do not repeat as well, after the decimal but only extends further, which is the property of the irrational number. We can also prove that root 6 is irrational, 1 by using the method of contradiction or the other for using the method of long division.

Some of the important properties of the square root are as follows:

If the number is the perfect square number, then there exists a perfect square root. If the no ends with the even number of 0 (0’s), then it could have the square root. The 2 square root values could be multiplied. For example, √3 could be multiplied by √2, then the result can be √6.

Is negative square root of 6 a natural number?

The square root of six is a rational number if six it is the perfect square. It is an irrational number if this is not a perfect square. so 6 is not a perfect square, this is an irrational number.

Learn more about  irrational number here https://brainly.com/question/4031928

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