The sum/difference of two functions is simply defined as the sum between their expression:
[tex](f\pm g)(x)=f(x)\pm g(x)[/tex]
So, we have
[tex](a+b)(x)=a(x)+b(x)=(4x+9)+(3x-5) = 7x+4[/tex]
[tex](a-b)(x)=a(x)-b(x)=(4x+9)-(3x-5) = x+14[/tex]
As for the composition, we have to compute
[tex](a\circ b)(x) = a(b(x))[/tex]
So, we have to write the expression for a and evaluate it at b(x):
[tex]a(x) = 4x+9 \implies a(b(x)) = a(3x-5) = 4(3x-5)+9 = 12x-20+9 = 12x-11[/tex]