contestada

A 200 N force is applied to a 50.0 kg object moving at 3.0 m/s. How fast will it be going at 4.0 s?

Respuesta :

Answer:

19.0 m/s

Explanation:

First of all, we can find the acceleration of the object by using Newton's second law:

[tex]F=ma[/tex]

where

F = 200 N is the net force applied to the object

m = 50.0 kg is the mass of the object

a is the acceleration

Solving for a,

[tex]a=\frac{F}{m}=\frac{200 N}{50.0 kg}=4.0 m/s^2[/tex]

Now we can find the final speed of the object:

[tex]v=u+at[/tex]

where

u = 3.0 m/s is the initial speed

a = 4.0 m/s^2 is the acceleration

t = 4.0 s is the time

Substituting,

[tex]v=3.0 m/s + (4.0 m/s^2)(4.0 s)=19.0 m/s[/tex]

ACCESS MORE