Two numbers have a difference of 28. What is the sum of their squares if it is a minimum?

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bekuang bekuang · Answer 1 · 2021-04-06T02:54:54+02:00

Answer:

392

Step-by-step explanation:

Squares get really big very quickly, so you don't want to use any bigger numbers. The biggest total of the squares would be from

using

1 and 28

1+28

2=1+784=785

2 and 27=4+729=733

142+14

2=196+196=392

The greater the difference between the two numbers, the bigger one of the numbers is going to be.

Therefore use two numbers with the smallest difference between them which will be

14 and 14

indritachandra1999 indritachandra1999 · Answer 2 · 2022-06-19T12:27:28+02:00

The minimum value of sum of their square is 392.

A mathematical statement consisting of an equal symbol between two algebraic expressions with the same value is known as an equation.

Let the Bigger no. = x

Let the Smaller no. = y

x - y = 28 (given)

(x - y)^2 = 28^2

x^2 + y^2 - 2xy = 784

x^2 + y^2 = 784 + 2xy

Let the value of x = 14 and y = -14 (By trial and error)

Hence, the minimum value of sum of squares will be 14^2 + 14^2 = 392.

Learn more about equations on:

https://brainly.com/question/2972832

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