Use the quadratic formula -b +/-√(b^2-4(ac)) / 2a
In the given formula a = 7, b = 23 and c = -10
Replace the letters with their values:
-23 +/-√(23^2 -4*(7*-10)) / 2*7
Simplify to get:
x = -23 + √809 / 14 or x = -23 - √809 / 14
Answer:
[tex]x=\frac{23- \sqrt{809}}{-14},\frac{23+\sqrt{809}}{-14}[/tex]
Step-by-step explanation:
Given : [tex]-7x^2 - 23x + 10 = 0[/tex]
To Find: What are the solutions of the quadratic equation below?
Solution:
[tex]-7x^2 - 23x + 10 = 0[/tex]
Solve the given equation using quadratic formula.
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
General form of quadratic equation: [tex]ax^2+bx+c=0[/tex]
On Comparing given equation with general form
a = -7
b = -23
c = 10
Substitute the values in the formula:
[tex]x=\frac{-(-23)\pm\sqrt{(-23)^2-4(-7)(10)}}{2(-7)}[/tex]
[tex]x=\frac{23\pm\sqrt{809}}{-14}[/tex]
[tex]x=\frac{23- \sqrt{809}}{-14},\frac{23+\sqrt{809}}{-14}[/tex]
Hence the solution of the quadratic equation is [tex]x=\frac{23- \sqrt{809}}{-14},\frac{23+\sqrt{809}}{-14}[/tex]
