Answer:
108.3 N
Explanation:
The maximum force of static friction acting on the box is given by:
[tex]F=\mu N[/tex]
where
[tex]\mu = 0.85[/tex] is the coefficient of static friction
N is the normal reaction of the table on the box
Since the box is in equilibrium along the vertical direction, the normal reaction N is equal to the weight of the box, so:
[tex]N=mg=(13 kg)(9.8 m/s^2)=127.4 N[/tex]
And so, the maximum force of static friction is
[tex]F=(0.85)(127.4 N)=108.3 N[/tex]
