Question

Solve x2 + 2x + 9 = 0. (2 points)

Answer 1

Answer: $x_1=-1+2i\sqrt{2}}}\\\\x_2=-1-2i\sqrt{2}}$

Step-by-step explanation:

Use que Quadratic formula:

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

Given the quadratic equation $x^2 + 2x + 9 = 0$, you can identify that:

$a=1\\ b=2\\ c=9$

Then, substitute values into the quadratic formula and simplify.

Remember that $\sqrt{-1}=i$

Then:

$x=\frac{-2\±\sqrt{2^2-4(1)(9)}}{2(1)}$

$x=\frac{-2\sqrt{-32}}{2}$

$x=\frac{-2\±4i\sqrt{2}}{2}\\\\x=\frac{2(-1\±2i\sqrt{2})}{2}\\\\\\x_1=-1+2i\sqrt{2}}}\\\\x_2=-1-2i\sqrt{2}}$

Answer 2

Answer:

Solution of given equation are,

x₁ =  -1 + 2i√2 and   x₂ =  -1 - 2i√2

Step-by-step explanation:

It s given a quadratic equation,

x² + 2x + 9 =0

To solve the equation

we have,

x = [-b ± √(b² - 4ac)]/2a

Here a = 1, b =2 and c = 9

x =  [-2 ± √(2² - 4* 1 * 9)]/2*1

x = [-2 ± √-32]/2

x = [-1 ± 2i√2]

x₁ =  -1 + 2i√2 and   x₂ =  -1 - 2i√2