Question

what is the percentage yield of carbon disulfide if the reaction of 32.0g of sulfur dioxide produces 12.0g of carbon disulfide?

Answer 1

Answer;

= 63.04 %  

Explanation;

The balanced equation for the reaction;

5 C + 2 SO2 → CS2 + 4 CO  

We can calculate the theoretical yield;

   = (32.0 g SO2) / (64 g C/mol) x (1/2) x (76.1418 g CS2/mol)

   = 19.035 g CS2 in theory  

But;

Percentage yield = Actual yield/theoretical yield × 100%

                              = (12.0 g) / ( 19.035 g) × 100%

                              = 0.6304 × 100%

                               = 63.04%