Question

A line passes through the point (5,-2) and has a slope of -1/3.Which equation models the line

Answer 1

Answer:

$y + 2= -\frac{1}{3}(x-5)$

Step-by-step explanation:

To write the equation of a line with a slope and a point, use the point slope form of the line. Substitute m = -1/3 and (5, -2).

$y - y_1 = m(x-x_1)\\y --2 = -\frac{1}{3}(x - 5)\\y + 2 = -\frac{1}{3}(x-5)$

You can convert to slope intercept form.

$y + 2 = -\frac{1}{3}(x-5)\\y + 2 = -\frac{1}{3}x + \frac{5}{3}\\y = -\frac{1}{3}x + \frac{5}{3} -2\\y = -\frac{1}{3}x - \frac{1}{3}$