The volume of concentrated 18M sulfuric acid is needed to prepare 250mL of a 6.0M solution is 83.3mL.
How do we calculate concentration?
Concentration in terms of molarity for this question will be calculated as:
M₁V₁ = M₂V₂, where
M₁ = molarity of sulphuric acid = 18M
V₁ = volume of sulphuric acid = ?
M₂ = molarity of final solution = 6M
V₂ = volume of final solution = 250mL
On putting these values on the above equation, we get
V₁ = (6)(250) / (18)
V₁ = 83.3
Hence required volume of sulphuric acid is 83.3mL.
To know more about molarity, visit the below link:
https://brainly.com/question/14469428
