Answer:
Part A) The triangles ABC and EDC are similar by AAA, because the three internal angles are equal in both triangles
Part B) The width of the river is about [tex]39\ ft[/tex]
Step-by-step explanation:
we know that
If two triangles are similar, then the ratio of its corresponding sides is equal and its corresponding angles are congruent
Part A) we know that
In this problem , triangles ABC and CDE are similar by AAA, because its corresponding angles are congruent
so
m<DCE=m<ACB -----> by vertical angles
m<EDC=m<ABC -----> is a right angle
m<DEC=m<CAB -----> the sum of the internal angles must be equal to 180 degrees
Part B) we know that
The triangles ABC and EDC are similar -------> see Part A
therefore
[tex]\frac{BC}{DC}=\frac{AB}{DE}[/tex]
substitute the values and solve for AB
[tex]\frac{65}{25}=\frac{AB}{15}[/tex]
[tex]AB=15*(\frac{65}{25})=39\ ft[/tex]