Question

The sum of the roots of x^2+6x-55=0

Answer 1

Answer:

The sum of the roots is $-6$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +6x-55=0$  

so

$a=1\\b=6\\c=-55$

substitute in the formula

$x=\frac{-6(+/-)\sqrt{6^{2}-4(1)(-55)}} {2(1)}$

$x=\frac{-6(+/-)\sqrt{256}} {2}$

$x=\frac{-6(+/-)16} {2}$

$x1=\frac{-6(+)16} {2}=5$

$x2=\frac{-6(-)16} {2}=-11$

The roots are $5,-11$

Find the sum of the roots

$5+(-11)=-6$

Answer 2

Answer:

The sum is -6