Answer:
The length of CI is 10 units.
Step-by-step explanation:
It is given that ABCD is a parallelogram and diagonals AC and BD intersect at point I.
The diagonals of a parallelogram bisect each other.
[tex]AI=CI[/tex]
[tex]AC=AI+CI[/tex]
[tex]AC=AI+AI[/tex] [tex][\because AI=CI][/tex]
[tex]AC=2AI[/tex]
[tex]3x-16=2(x-2)[/tex]
[tex]3x-16=2x-4[/tex]
[tex]3x-2x=16-4[/tex]
[tex]x=12[/tex]
The value of x is 12.
[tex]CI=AI=x-2=12-2=10[/tex]
Therefore the length of CI is 10 units.