Please help me with this question

Answer:
Step-by-step explanation:
[tex]\csc x=\dfrac{1}{\sin x}\\\\\sin(-x)=-\sin x\to\csc(-x)=-\csc x\\\\\sin\theta=\dfrac{20}{29}\to\csc(-\theta)=-\csc\theta=-\dfrac{1}{\frac{20}{29}}=-\dfrac{29}{20}[/tex]
[tex]0^o<\theta<90^o\to\text{I Quadrant}\to\sin\theta>0\\\\-\theta\to\text{IV Quadrant}\to\sin\theta<0[/tex]