[tex]\bf \textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &10\\ t=\textit{elapsed time}\dotfill &0.003\\ h=\textit{half-life}\dotfill &0.001 \end{cases} \\\\\\ A=10\left( \frac{1}{2} \right)^{\frac{0.003}{0.001}}\implies A=10\left( \frac{1}{2} \right)^3\implies A=1.25[/tex]