Question

Parallelogram abcd has the coordinates of a(-1,10) and c(5,4). Find the coordinates of where diagonals ac and bd intersect

Answer 1

Answer:

The coordinates of where diagonals ac and bd intersect at (2,7)

Step-by-step explanation:

we are given coordinates as a(-1,10) and c(5,4)

we know that diagonals of parallelogram always bisect each other

Let's assume O is the intersection point between diagonals

So, point O bisects line ac into two equal parts

So, point O is the mid-point of ac

so, we can find point O

we get

$O=(\frac{-1+5}{2}, \frac{10+4}{2})$

now, we can simplify it

and we get

$O=(\frac{4}{2}, \frac{14}{2})$

$O=(2,7)$

So,

The coordinates of where diagonals ac and bd intersect at (2,7)