the area A of a rectangle parking lot is given by the equation A=16s^2+25. jacob knows the area of the parking lot and wants to find s. Solve A=16s^2+25 for s

Respuesta :

Answer:

s = sqrt(A - 25)/4

Step-by-step explanation:

A = 16s^2 + 25

Switch sides.

16s^2 + 25 = A

Subtract 25 from both sides.

16s^2 = A - 25

Divide both sides by 16

s^2 = (A - 25)/16

Take the square root of each side.

s = sqrt[(A - 25)/16]

s = sqrt(A - 25)/4

Answer:

The required form in terms of A the value of s is [tex]s=\sqrt{\frac{A-25}{16}}[/tex]

Step-by-step explanation:

Given : The area A of a rectangle parking lot is given by the equation[tex]A=16s^2+25[/tex]. Jacob knows the area of the parking lot.

To find : Solve [tex]A=16s^2+25[/tex] for s?

Solution :

The area A of a rectangle parking lot is given by the equation

[tex]A=16s^2+25[/tex]

To solve the given expression for s, we have to separate the s and take it to one side.

Subtract 25 from both side,

[tex]A-25=16s^2+25-25[/tex]

[tex]A-25=16s^2[/tex]

Divide both side by 16,

[tex]\frac{A-25}{16}=\frac{16s^2}{16}[/tex]

[tex]\frac{A-25}{16}=s^2[/tex]

Taking root both side,

[tex]\sqrt{\frac{A-25}{16}}=\sqrt{s^2}[/tex]

[tex]\sqrt{\frac{A-25}{16}}=s[/tex]

So, The required form in terms of A the value of s is [tex]s=\sqrt{\frac{A-25}{16}}[/tex]