In each column of the table, you're expected to find the approximate value of [tex]\dfrac{x^2}{\sin x}[/tex]. For example, if [tex]x=-0.03[/tex], then you'd find [tex]\dfrac{x^2}{\sin x}\approx-0.0300[/tex], while if [tex]x=0.03[/tex], then [tex]\dfrac{x^2}{\sin x}\approx0.300[/tex].
As you fill in the table, you'll see that for values of [tex]x[/tex] to either side of [tex]x=0[/tex] the value of [tex]\dfrac{x^2}{\sin x}[/tex] gradually gets closer to 0 too. So the limit must be 0, and the second option is correct.
