Answer:
4th option
Step-by-step explanation:
given
sinΘ = [tex]\frac{5}{13}[/tex] and cosΘ = [tex]\frac{12}{13}[/tex] , then
( [tex]\frac{5}{13}[/tex] )² + ( [tex]\frac{12}{13}[/tex] )²
= [tex]\frac{25}{169}[/tex] + [tex]\frac{144}{169}[/tex]
= [tex]\frac{25+144}{169}[/tex]
= [tex]\frac{169}{169}[/tex]
= 1
showing sin²Θ + cos²Θ = 1
