Seudónimo Seudónimo
  • 28-12-2018
  • Mathematics
contestada

Im'm in a very desperate situation right now any help is literally welcomed thanks

Imm in a very desperate situation right now any help is literally welcomed thanks class=

Respuesta :

Shreyash Shreyash
  • 28-12-2018

[tex]( \frac{ - 1 + 1}{2}, \frac{0 - 2}{2}) [/tex]


it's the correct answer
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