Question

For the unbalanced equation, what is the coefficient for C5H10? ? C5H10 (l) +? O2 (g) →? CO2 (g) +? H2O (g) A. 2 B. 4 C. 10 D. 6 E. 1

Answer 1

1C5H10 + 15/2O2 => 5CO2 + 5H2O

Answer 2

Explanation:

Balanced equation is defined as the equation which contains same number of atoms on both reactant and product side.

For example, $C_{5}H_{10}(l) + O_{2} \rightarrow CO_{2}(g) + H_{2}O(g)$

Number of atoms on reactant side are as follows.

• C = 5

• H = 10

• O = 2

Number of atoms on product side are as follows.

• C = 1

• H = 2

• O = 3

So, to balance this equation we will multiply $CO_{2}$ on product side by 5 and also multiply $H_{2}O$ by 5. On the reactant side, we multiply $O_{2}$ by  $\frac{15}{2}$. Therefore, the balanced equation is as follows.

      $C_{5}H_{10}(l) + \frac{15}{2}O_{2} \rightarrow 5CO_{2}(g) + 5H_{2}O(g)$

Thus, we can conclude that for the given unbalanced equation the coefficient for $C_5H_10$ is 1.