Question

Area of the shaded segment=

Answer 1

Alright, since the radius is 6, pi(6)^2=36pi is your area. Since 60/360=1/6, that means the overall section is 36pi/6=6pi. Since this can be made 6 times,
AB = 6 as 36/6=6 and OAB is equilateral, making the area of that
sqrt(3)*(6^2)/4 = 9sqrt(3). Therefore, the area of the shaded segment is
 6pi-9sqrt(3)

Answer 2

Answer:  6π-9√3 unit²

Step-by-step explanation:

area of sector OBAO =Area of circle/6      (∵ 60°=360°/6)

                                    =  π×6²/6

                                    =  6π unit²

now, area of triangle OAB=√3×6²/4  (∵ it is an equilateral triangle and area of equilateral triangle=√3×side²/4)

                                             =9√3 unit²

Area of shaded region= area of sector OBAO- area of triangle OAB

                                     = 6π-9√3 unit²