Question

Jerome and his brother Jake are painting on square canvases. Let x represent the side length of Jake's canvas. If Jerome's canvas has a side length twice that of Jake's canvas, what is the difference in area between Jerome and Jakes canvases?

Answer 1

Answer:

3$x^{2}$

Step-by-step explanation:

Jake's canvas is x times x,

which is $x^{2}$.

Jerome's canvas is 2x times 2x,

which is $(2x)^{2}$ = $4x^{2}$.

The difference in area would be

$4x^{2} -x^{2}=3x^{2}$